Implement the built-in Parameters<T> generic without using it.
For example:
const foo = (arg1: string, arg2: number): void => {}
type FunctionParamsType = MyParameters<typeof foo> // [arg1: string, arg2: number]
import type { Equal, Expect } from '@type-challenges/utils'
function foo(arg1: string, arg2: number): void {}
function bar(arg1: boolean, arg2: { a: 'A' }): void {}
function baz(): void {}
type cases = [
Expect<Equal<MyParameters<typeof foo>, [string, number]>>,
Expect<Equal<MyParameters<typeof bar>, [boolean, { a: 'A' }]>>,
Expect<Equal<MyParameters<typeof baz>, []>>,
]