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00151-extreme-query-string-parser
Extreme
template-literal

チャレンジのソース: type-challenges/00151-extreme-query-string-parser

You're required to implement a type-level parser to parse URL query string into a object literal type.

Some detailed requirements:

  • Value of a key in query string can be ignored but still be parsed to true. For example, 'key' is without value, so the parser result is { key: true }.
  • Duplicated keys must be merged into one. If there are different values with the same key, values must be merged into a tuple type.
  • When a key has only one value, that value can't be wrapped into a tuple type.
  • If values with the same key appear more than once, it must be treated as once. For example, key=value&key=value must be treated as key=value only.

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テストケースの出典: type-challenges/00151-extreme-query-string-parser/test-cases.ts
import type { Equal, Expect } from '@type-challenges/utils'

type cases = [
  Expect<Equal<ParseQueryString<''>, {}>>,
  Expect<Equal<ParseQueryString<'k1'>, { k1: true }>>,
  Expect<Equal<ParseQueryString<'k1&k1'>, { k1: true }>>,
  Expect<Equal<ParseQueryString<'k1&k2'>, { k1: true, k2: true }>>,
  Expect<Equal<ParseQueryString<'k1=v1'>, { k1: 'v1' }>>,
  Expect<Equal<ParseQueryString<'k1=v1&k1=v2'>, { k1: ['v1', 'v2'] }>>,
  Expect<Equal<ParseQueryString<'k1=v1&k2=v2'>, { k1: 'v1', k2: 'v2' }>>,
  Expect<Equal<ParseQueryString<'k1=v1&k2=v2&k1=v2'>, { k1: ['v1', 'v2'], k2: 'v2' }>>,
  Expect<Equal<ParseQueryString<'k1=v1&k2'>, { k1: 'v1', k2: true }>>,
  Expect<Equal<ParseQueryString<'k1=v1&k1=v1'>, { k1: 'v1' }>>,
  Expect<Equal<ParseQueryString<'k1=v1&k1=v2&k1=v1'>, { k1: ['v1', 'v2'] }>>,
  Expect<Equal<ParseQueryString<'k1=v1&k2=v1&k1=v2&k1=v1'>, { k1: ['v1', 'v2'], k2: 'v1' }>>,
  Expect<Equal<ParseQueryString<'k1=v1&k2=v2&k1=v2&k1=v3'>, { k1: ['v1', 'v2', 'v3'], k2: 'v2' }>>,
  Expect<Equal<ParseQueryString<'k1=v1&k1'>, { k1: ['v1', true] }>>,
  Expect<Equal<ParseQueryString<'k1&k1=v1'>, { k1: [true, 'v1'] }>>,
]