27862-medium-cartesianproduct
Medium
union

Given 2 sets (unions), return its Cartesian product in a set of tuples, e.g.

CartesianProduct<1 | 2, 'a' | 'b'> 
// [1, 'a'] | [2, 'a'] | [1, 'b'] | [2, 'b']

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import type { Equal, Expect } from '@type-challenges/utils'

type cases = [
  Expect<Equal<CartesianProduct<1 | 2, 'a' | 'b'>, [2, 'a'] | [1, 'a'] | [2, 'b'] | [1, 'b']>>,
  Expect<Equal<CartesianProduct<1 | 2 | 3, 'a' | 'b' | 'c' >, [2, 'a'] | [1, 'a'] | [3, 'a'] | [2, 'b'] | [1, 'b'] | [3, 'b'] | [2, 'c'] | [1, 'c'] | [3, 'c']>>,
  Expect<Equal<CartesianProduct<1 | 2, 'a' | never>, [2, 'a'] | [1, 'a'] >>,
  Expect<Equal<CartesianProduct<'a', Function | string>, ['a', Function] | ['a', string]>>,
]