通过实现一个CountElementNumberToObject方法，统计数组中相同元素的个数
type Simple1 = CountElementNumberToObject<[]> // return {}
type Simple2 = CountElementNumberToObject<[1,2,3,4,5]>
/*
return {
1: 1,
2: 1,
3: 1,
4: 1,
5: 1
}
*/
type Simple3 = CountElementNumberToObject<[1,2,3,4,5,[1,2,3]]>
/*
return {
1: 2,
2: 2,
3: 2,
4: 1,
5: 1
}
*/
import type { Equal, Expect } from '@type-challenges/utils'
type cases = [
Expect<Equal<CountElementNumberToObject<[1, 2, 3, 4, 5]>, {
1: 1
2: 1
3: 1
4: 1
5: 1
} >>,
Expect<Equal<CountElementNumberToObject<[1, 2, 3, 4, 5, [1, 2, 3]]>, {
1: 2
2: 2
3: 2
4: 1
5: 1
}>>,
Expect<Equal<CountElementNumberToObject<[1, 2, 3, 4, 5, [1, 2, 3, [4, 4, 1, 2]]]>, {
1: 3
2: 3
3: 2
4: 3
5: 1
}>>,
Expect<Equal<CountElementNumberToObject<[never]>, {}>>,
Expect<Equal<CountElementNumberToObject<['1', '2', '0']>, {
0: 1
1: 1
2: 1
}>>,
Expect<Equal<CountElementNumberToObject<['a', 'b', ['c', ['d']]]>, {
'a': 1
'b': 1
'c': 1
'd': 1
}>>,
]